Distance between 70 Mile House BC and Clinton BC
The distance from 70 Mile House to Clinton is 21 miles by road. Road takes approximately 22 minutes.
| Shortest distance by air | 17 mi ✈️ |
| Car route length | 20.5 mi 🚗 |
| Driving time | 22 min |
| Fuel amount | 0.7 gal |
| Fuel cost | 2.7 USD |
| Point | Distance | Time | Fuel | |
| 70 Mile House | 0 mi | 00 min | 0.0 gal | |
|
97 21 mi, 22 min
|
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| Clinton | 21 mi | 22 min | 0.7 gal | |
Hotels of Clinton
Frequently Asked Questions
How much does it cost to drive from 70 Mile House to Clinton?
Fuel cost: 2.7 USD
This fuel cost is calculated as: (Route length 20.5 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.93 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from 70 Mile House to Clinton?
Driving time: 22 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 20 mi with a maximum speed 56 mph = 20 min
- 1 mi with a maximum speed 31 mph = 1 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is 70 Mile House to Clinton by land?
The distance between 70 Mile House and Clinton is 20.5 mi by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of 70 Mile House and Clinton respectively.
Where is 70 Mile House in relation to Clinton?
70 Mile House is located 17 mi north-east of Clinton.
70 Mile House has geographic coordinates: latitude 51.3135, longitude -121.3936.
Clinton has geographic coordinates: latitude 51.09277, longitude -121.58941.
Which highway goes from 70 Mile House to Clinton?
The route from 70 Mile House to Clinton follows 97.