Distance between Arnold MO and Cherokee Pass MO
The distance from Arnold to Cherokee Pass is 76 miles by road including 39 miles on motorways. Road takes approximately 1 hour and 19 minutes and goes through Festus, Farmington, Pevely and Leadington.
| Shortest distance by air | 65 mi ✈️ |
| Car route length | 75.8 mi 🚗 |
| Driving time | 1 h 19 min |
| Fuel amount | 2.6 gal |
| Fuel cost | 10 USD |
| Point | Distance | Time | Fuel | |
| Arnold | 0 mi | 00 min | 0.0 gal | |
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I 55 12 mi, 12 min
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| Pevely | 12 mi | 12 min | 0.4 gal | |
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I 55 4 mi, 03 min
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| Festus | 17 mi | 15 min | 0.5 gal | |
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I 55 US 67 16 mi, 17 min
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| Halifax | 32 mi | 32 min | 0.9 gal | |
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US 67 16 mi, 17 min
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| Leadington | 48 mi | 49 min | 1.6 gal | |
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US 67 4 mi, 03 min
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| Farmington | 52 mi | 53 min | 1.7 gal | |
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US 67 14 mi, 14 min
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| Catherine Place | 66 mi | 1 h 08 min | 2.0 gal | |
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US 67 11 mi, 11 min
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| Cherokee Pass | 76 mi | 1 h 19 min | 2.6 gal | |
Frequently Asked Questions
How much does it cost to drive from Arnold to Cherokee Pass?
Fuel cost: 10 USD
This fuel cost is calculated as: (Route length 75.8 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.89 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Arnold to Cherokee Pass?
Driving time: 1 h 19 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 15 mi with a maximum speed 68 mph = 13 min
- 12 mi with a maximum speed 65 mph = 11 min
- 11 mi with a maximum speed 60 mph = 11 min
- 11 mi with a maximum speed 56 mph = 11 min
- 25 mi with a maximum speed 50 mph = 30 min
- 1 mi with a maximum speed 31 mph = 1 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Arnold to Cherokee Pass by land?
The distance between Arnold and Cherokee Pass is 75.8 mi by road including 39.1 mi on motorways.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Arnold and Cherokee Pass respectively.
How far is Arnold to Cherokee Pass by plane?
The shortest distance (air line, as the crow flies) between Arnold and Cherokee Pass is 65.2 mi.
This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Arnold and Cherokee Pass respectively. Actual distance between airports may be different.
How many hours is Arnold from Cherokee Pass by plane?
Boeing 737 airliner needs 7 min to cover the distance of 65 mi at a cruising speed of 497 mph.
Small plane "Cessna 172" needs 28 min to flight this distance at average speed of 136 mph.
This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.
How long is a helicopter ride from Arnold to Cherokee Pass?
Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 26 min to cover the distance of 65 mi at a cruising speed of 149 mph.
Popular "Robinson R44" needs 30 min to flight this distance at average speed of 130 mph.
This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.
What city is halfway between Arnold and Cherokee Pass?
The halfway point between Arnold and Cherokee Pass is Halifax. It is located about 6 mi from the exact midpoint by road.
The distance from Halifax to Arnold is 32 mi and driving will take about 32 min. The road between Halifax and Cherokee Pass has length 44 mi and will take approximately 47 min.
The other cities located close to halfway point:
Where is Arnold in relation to Cherokee Pass?
Arnold is located 65 mi north of Cherokee Pass.
Arnold has geographic coordinates: latitude 38.43283, longitude -90.37762.
Cherokee Pass has geographic coordinates: latitude 37.4895, longitude -90.30512.
Which highway goes from Arnold to Cherokee Pass?
The route from Arnold to Cherokee Pass follows US 67.
Other minor sections pass along the road:
- I 55: 17 mi
- MO 32: 4 mi