Distance between Avery OH and Sand Hill OH
The distance from Avery to Sand Hill is 7 miles by road. Road takes approximately 8 minutes and goes through Avery and Bloomingville.
Shortest distance by air | 7 mi ✈️ |
Car route length | 7.5 mi 🚗 |
Driving time | 8 min |
Fuel amount | 0.2 gal |
Fuel cost | 0.9 USD |
Point | Distance | Time | Fuel | |
Avery | 0 mi | 00 min | 0.0 gal | |
US 250 7 mi, 08 min
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Sand Hill | 7 mi | 08 min | 0.0 gal |
Frequently Asked Questions
How much does it cost to drive from Avery to Sand Hill?
Fuel cost: 0.9 USD
This fuel cost is calculated as: (Route length 7.5 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.82 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Avery to Sand Hill?
Driving time: 8 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 7 mi with a maximum speed 50 mph = 8 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Avery to Sand Hill by land?
The distance between Avery and Sand Hill is 7.5 mi by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Avery and Sand Hill respectively.
Where is Avery in relation to Sand Hill?
Avery is located 7 mi east of Sand Hill.
Avery has geographic coordinates: latitude 41.3328, longitude -82.62477.
Sand Hill has geographic coordinates: latitude 41.36144, longitude -82.75546.
Which highway goes from Avery to Sand Hill?
The route from Avery to Sand Hill follows US 250.