The distance from Bloomsburg to Wapella is 1,737 miles by road including 1,424 miles on motorways. Road takes approximately 27 hours and 26 minutes and goes through Elyria, Toledo, South Bend, Chicago, Janesville, Madison and Eau Claire.
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How long is a car ride from Bloomsburg to Wapella?
Driving time:
27 h 26 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
1,182 mi with a maximum speed 68 mph = 17 h 23 min
32 mi with a maximum speed 65 mph = 29 min
53 mi with a maximum speed 62 mph = 50 min
31 mi with a maximum speed 60 mph = 31 min
275 mi with a maximum speed 56 mph = 4 h 53 min
4 mi with a maximum speed 56 mph = 3 min
22 mi with a maximum speed 55 mph = 23 min
132 mi with a maximum speed 50 mph = 2 h 39 min
2 mi with a maximum speed 45 mph = 3 min
1 mi with a maximum speed 37 mph = 2 min
1 mi with a maximum speed 31 mph = 2 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Bloomsburg to Wapella by land?
The distance between Bloomsburg and Wapella is 1,736.7 mi by road including 1,424.2 mi on motorways.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Bloomsburg and Wapella respectively.
How far is Bloomsburg to Wapella by plane?
The shortest distance (air line, as the crow flies) between Bloomsburg and Wapella is 1,380.1 mi.
This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Bloomsburg and Wapella respectively. Actual distance between airports may be different.
How many hours is Bloomsburg from Wapella by plane?
Boeing 737 airliner needs 2 h 46 min to cover the distance of 1,380 mi at a cruising speed of 497 mph.
Small plane "Cessna 172" needs 10 h 5 min to flight this distance at average speed of 136 mph.
This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.
How long is a helicopter ride from Bloomsburg to Wapella?
Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 9 h 15 min to cover the distance of 1,380 mi at a cruising speed of 149 mph.
Popular "Robinson R44" needs 10 h 34 min to flight this distance at average speed of 130 mph.
This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.
What city is halfway between Bloomsburg and Wapella?
The halfway point between Bloomsburg and Wapella is Camp Douglas. It is located about 2 mi from the exact midpoint by road.
The distance from Camp Douglas to Bloomsburg is 871 mi and driving will take about 13 h. The road between Camp Douglas and Wapella has length 866 mi and will take approximately 14 h 25 min.
The other cities located close to halfway point:
Oakdale is in 876 mi from Bloomsburg and 861 mi from Wapella
Wisconsin Dells is in 846 mi from Bloomsburg and 890 mi from Wapella
Millston is in 898 mi from Bloomsburg and 839 mi from Wapella
Where is Bloomsburg in relation to Wapella?
Bloomsburg is located 1,380 mi south-east of Wapella.
Bloomsburg has geographic coordinates: latitude 41.00412, longitude -76.45382.
Wapella has geographic coordinates: latitude 50.26607, longitude -101.97411.
Which highway goes from Bloomsburg to Wapella?
The route from Bloomsburg to Wapella follows I 80, I 90, I 94, PTH 1, I 29, US 81, I 39.