Distance between Cranbrook BC and Fort St. John BC

The distance from Cranbrook to Fort St. John is 685 miles by road including 17 miles on motorways. Road takes approximately 12 hours and 43 minutes and goes through Grande Prairie, Dawson Creek, Jasper, Grande Cache, Wembley, Beaverlodge and Pine Valley.

Shortest distance by air 511 mi ✈️
Car route length 684.8 mi 🚗
Driving time 12 h 43 min
Fuel amount 23.3 gal
Fuel cost 90.9 USD
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City
Town
Village
Hamlet
Motorway
Primary
Secondary
Unclassified
Point Distance Time Fuel
Cranbrook 0 mi 0:00 00 min 0.0 gal
3 93 314 mi, 5 h 52 min
Jasper 314 mi 5:52 5 h 52 min 10.2 gal
93 40 129 mi, 2 h 21 min
Grande Cache 442 mi 8:13 8 h 13 min 14.9 gal
40 117 mi, 2 h 06 min
Grande Prairie 559 mi 10:19 10 h 19 min 18.9 gal
40 43 14 mi, 16 min
Wembley 574 mi 10:35 10 h 35 min 19.3 gal
43 14 mi, 15 min
Beaverlodge 588 mi 10:51 10 h 51 min 19.8 gal
43 53 mi, 1 h 00 min
Dawson Creek 641 mi 11:51 11 h 51 min 21.6 gal
97 23 mi, 24 min
Pine Valley 664 mi 12:16 12 h 16 min 22.5 gal
97 12 mi, 13 min
Taylor 676 mi 12:30 12 h 30 min 22.9 gal
97 11 mi, 12 min
Fort St. John 687 mi 12:43 12 h 43 min 23.2 gal
City
Town
Village
Hamlet
Motorway
Primary
Secondary
Unclassified
Point Distance Time Fuel
Cranbrook 0 mi 0:00 00 min 0.0 gal
3 95 16 mi, 18 min
Fort Steele 16 mi 0:18 18 min 0.2 gal
93 17 mi, 18 min
Skookumchuck 34 mi 0:37 37 min 1.1 gal
93 19 mi, 20 min
Canal Flats 52 mi 0:57 57 min 1.7 gal
93 19 mi, 20 min
Fairmont Hot Springs 71 mi 1:18 1 h 18 min 2.3 gal
93 7 mi, 08 min
Windermere 79 mi 1:26 1 h 26 min 2.6 gal
93 12 mi, 17 min
Radium Hot Springs 91 mi 1:43 1 h 43 min 3.0 gal
93 80 mi, 1 h 29 min
Lake Louise 171 mi 3:13 3 h 13 min 5.8 gal
1 93 142 mi, 2 h 38 min
Jasper 314 mi 5:51 5 h 51 min 10.2 gal
93 16 48 mi, 53 min
Entrance 361 mi 6:45 6 h 45 min 12.3 gal
40 81 mi, 1 h 27 min
Grande Cache 442 mi 8:13 8 h 13 min 14.9 gal
40 117 mi, 2 h 06 min
Grande Prairie 559 mi 10:19 10 h 19 min 18.9 gal
40 43 14 mi, 16 min
Wembley 574 mi 10:35 10 h 35 min 19.3 gal
43 14 mi, 15 min
Beaverlodge 588 mi 10:51 10 h 51 min 19.8 gal
43 45 mi, 50 min
Pouce Coupe 633 mi 11:41 11 h 41 min 21.5 gal
2 8 mi, 10 min
Dawson Creek 641 mi 11:51 11 h 51 min 21.6 gal
97 23 mi, 24 min
Pine Valley 664 mi 12:16 12 h 16 min 22.5 gal
97 12 mi, 13 min
Taylor 676 mi 12:30 12 h 30 min 22.9 gal
97 11 mi, 12 min
Fort St. John 687 mi 12:42 12 h 42 min 23.2 gal

Frequently Asked Questions

How much does it cost to drive from Cranbrook to Fort St. John?

Fuel cost: 90.9 USD

This fuel cost is calculated as: (Route length 684.8 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.9 USD / gal)

You can adjust fuel consumption and fuel price here.

How long is a car ride from Cranbrook to Fort St. John?

Driving time: 12 h 43 min

This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.

  • 458 mi with a maximum speed 56 mph = 8 h 10 min
  • 167 mi with a maximum speed 56 mph = 2 h 58 min
  • 20 mi with a maximum speed 50 mph = 24 min
  • 24 mi with a maximum speed 43 mph = 33 min
  • 6 mi with a maximum speed 37 mph = 8 min
  • 7 mi with a maximum speed 31 mph = 14 min
  • 4 mi with a maximum speed 19 mph = 11 min

The calculated driving time does not take into account intermediate stops and traffic jams.

How far is Cranbrook to Fort St. John by land?

The distance between Cranbrook and Fort St. John is 684.8 mi by road including 17.4 mi on motorways.

Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Cranbrook and Fort St. John respectively.

How far is Cranbrook to Fort St. John by plane?

The shortest distance (air line, as the crow flies) between Cranbrook and Fort St. John is 511.4 mi.

This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Cranbrook and Fort St. John respectively. Actual distance between airports may be different.

How many hours is Cranbrook from Fort St. John by plane?

Boeing 737 airliner needs 1 h 1 min to cover the distance of 511 mi at a cruising speed of 497 mph.

Small plane "Cessna 172" needs 3 h 44 min to flight this distance at average speed of 136 mph.

This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.

How long is a helicopter ride from Cranbrook to Fort St. John?

Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 3 h 25 min to cover the distance of 511 mi at a cruising speed of 149 mph.

Popular "Robinson R44" needs 3 h 55 min to flight this distance at average speed of 130 mph.

This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.

What city is halfway between Cranbrook and Fort St. John?

The halfway point between Cranbrook and Fort St. John is Entrance. It is located about 19 mi from the exact midpoint by road.

The distance from Entrance to Cranbrook is 361 mi and driving will take about 6 h 45 min. The road between Entrance and Fort St. John has length 324 mi and will take approximately 5 h 57 min.

The other cities located close to halfway point:

  • Jasper is in 314 mi from Cranbrook and 372 mi from Fort St. John
  • Grande Cache is in 442 mi from Cranbrook and 242 mi from Fort St. John

Where is Cranbrook in relation to Fort St. John?

Cranbrook is located 511 mi south-east of Fort St. John.

Cranbrook has geographic coordinates: latitude 49.50916, longitude -115.76019.

Fort St. John has geographic coordinates: latitude 56.25098, longitude -120.83588.

Which highway goes from Cranbrook to Fort St. John?

The route from Cranbrook to Fort St. John follows 93, 40, 95.

Other minor sections pass along the road:

  • 43: 51 mi
  • 97: 45 mi
  • 16: 44 mi
  • 2: 21 mi
  • 1: 17 mi
  • 3: 4 mi
  • 49: 3 mi
  • 93A: 1 mi
The distance between Cranbrook and Fort St. John is ranked 17,163rd in the ranking popularity.
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