Distance between Lawrence KS and Leawood KS

The distance from Lawrence to Leawood is 40 miles by road including 33 miles on motorways. Road takes approximately 40 minutes and goes through Olathe, Kansas City, Eudora, De Soto, Lenexa and Prairie Village.

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City
Town
Village
Hamlet
Motorway
Primary
Secondary
Unclassified
Point Distance Time Fuel
Lawrence 0 mi 0:00 00 min 0.0 gal
KS 10 10 mi, 11 min
Eudora 10 mi 0:11 11 min 0.3 gal
KS 10 8 mi, 07 min
De Soto 18 mi 0:18 18 min 0.5 gal
KS 10 7 mi, 06 min
Lenexa 25 mi 0:25 25 min 0.7 gal
KS 10 I 435 15 mi, 15 min
Leawood 40 mi 0:40 40 min 1.2 gal

Frequently Asked Questions

How much does it cost to drive from Lawrence to Leawood?

Fuel cost: 5.4 USD

This fuel cost is calculated as: (Route length 40.4 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.93 USD / gal)

You can adjust fuel consumption and fuel price here.

How long is a car ride from Lawrence to Leawood?

Driving time: 40 min

This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.

  • 21 mi with a maximum speed 68 mph = 18 min
  • 10 mi with a maximum speed 65 mph = 8 min
  • 2 mi with a maximum speed 55 mph = 2 min
  • 3 mi with a maximum speed 50 mph = 3 min
  • 1 mi with a maximum speed 45 mph = 1 min
  • 2 mi with a maximum speed 35 mph = 3 min
  • 1 mi with a maximum speed 31 mph = 1 min

The calculated driving time does not take into account intermediate stops and traffic jams.

How far is Lawrence to Leawood by land?

The distance between Lawrence and Leawood is 40.4 mi by road including 32.9 mi on motorways.

Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Lawrence and Leawood respectively.

How far is Lawrence to Leawood by plane?

The shortest distance (air line, as the crow flies) between Lawrence and Leawood is 33.6 mi.

This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Lawrence and Leawood respectively. Actual distance between airports may be different.

How many hours is Lawrence from Leawood by plane?

Boeing 737 airliner needs 4 min to cover the distance of 34 mi at a cruising speed of 497 mph.

Small plane "Cessna 172" needs 14 min to flight this distance at average speed of 136 mph.

This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.

How long is a helicopter ride from Lawrence to Leawood?

Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 13 min to cover the distance of 34 mi at a cruising speed of 149 mph.

Popular "Robinson R44" needs 15 min to flight this distance at average speed of 130 mph.

This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.

What city is halfway between Lawrence and Leawood?

The halfway point between Lawrence and Leawood is De Soto. It is located about 2 mi from the exact midpoint by road.

The distance from De Soto to Lawrence is 18 mi and driving will take about 18 min. The road between De Soto and Leawood has length 22 mi and will take approximately 22 min.

The other cities located close to halfway point:

  • Lenexa is in 25 mi from Lawrence and 15 mi from Leawood

Where is Lawrence in relation to Leawood?

Lawrence is located 34 mi west of Leawood.

Lawrence has geographic coordinates: latitude 38.97193, longitude -95.23595.

Leawood has geographic coordinates: latitude 38.96667, longitude -94.6169.

Which highway goes from Lawrence to Leawood?

The route from Lawrence to Leawood follows KS 10.

Other minor sections pass along the road:

  • I 435: 8 mi
  • US 50: 7 mi
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