Distance between Martinsburg WV and Berkeley WV
The distance from Martinsburg to Berkeley is 4 miles by road. Road takes approximately 6 minutes and goes through Bessemer, Hainesville and Falling Waters.
Shortest distance by air | 4 mi ✈️ |
Car route length | 4.3 mi 🚗 |
Driving time | 6 min |
Fuel amount | 0.2 gal |
Fuel cost | 0.6 USD |
Point | Distance | Time | Fuel | |
Martinsburg | 0 mi | 00 min | 0.0 gal | |
US 11 4 mi, 06 min
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Berkeley | 4 mi | 06 min | 0.1 gal |
Frequently Asked Questions
How much does it cost to drive from Martinsburg to Berkeley?
Fuel cost: 0.6 USD
This fuel cost is calculated as: (Route length 4.3 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.82 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Martinsburg to Berkeley?
Driving time: 6 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 3 mi with a maximum speed 50 mph = 4 min
- 1 mi with a maximum speed 31 mph = 2 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Martinsburg to Berkeley by land?
The distance between Martinsburg and Berkeley is 4.3 mi by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Martinsburg and Berkeley respectively.
Where is Martinsburg in relation to Berkeley?
Martinsburg is located 4 mi south-west of Berkeley.
Martinsburg has geographic coordinates: latitude 39.45608, longitude -77.96377.
Berkeley has geographic coordinates: latitude 39.50315, longitude -77.92723.
Which highway goes from Martinsburg to Berkeley?
The route from Martinsburg to Berkeley follows US 11, WV 9.
Other minor sections pass along the road:
- CR 12: 1 mi
- WV 45: 1 mi