Distance between Ramseysburg NJ and Columbia NJ
The distance from Ramseysburg to Columbia is 4 miles by road. Road takes approximately 4 minutes and goes through Portland, Delaware and Manunka Chunk.
| Shortest distance by air | 4 mi ✈️ |
| Car route length | 3.7 mi 🚗 |
| Driving time | 4 min |
| Fuel amount | 0.1 gal |
| Fuel cost | 0.5 USD |
| Point | Distance | Time | Fuel | |
| Delaware | 0 mi | 00 min | 0.0 gal | |
|
US 46 4 mi, 04 min
|
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| Portland | 4 mi | 04 min | 0.1 gal | |
Hotels of Columbia
Frequently Asked Questions
How much does it cost to drive from Ramseysburg to Columbia?
Fuel cost: 0.5 USD
This fuel cost is calculated as: (Route length 3.7 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.93 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Ramseysburg to Columbia?
Driving time: 4 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 3 mi with a maximum speed 50 mph = 3 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Ramseysburg to Columbia by land?
The distance between Ramseysburg and Columbia is 3.7 mi by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Ramseysburg and Columbia respectively.
Where is Ramseysburg in relation to Columbia?
Ramseysburg is located 4 mi south-east of Columbia.
Ramseysburg has geographic coordinates: latitude 40.88342, longitude -75.05935.
Columbia has geographic coordinates: latitude 40.9262, longitude -75.09268.
Which highway goes from Ramseysburg to Columbia?
The route from Ramseysburg to Columbia follows US 46.