Distance between Vicente Guerrero and San Francisco Javier de Satevó
The distance from Vicente Guerrero to San Francisco Javier de Satevó is 114 miles by road. Road takes approximately 2 hours and 6 minutes and goes through Cuauhtémoc, Basúchil, Sáenz, Páramo de Morelos, Santa Isabel and Rancho de Peña.
| Shortest distance by air | 93 mi ✈️ |
| Car route length | 113.7 mi 🚗 |
| Driving time | 2 h 6 min |
| Fuel amount | 3.9 gal |
| Fuel cost | 15.2 USD |
| Toll roads cost | 110 MXN |
| Point | Distance | Time | Fuel | |
| Vicente Guerrero | 0 mi | 00 min | 0.0 gal | |
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CHIH 11 7 mi, 08 min
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| Basúchil | 7 mi | 08 min | 0.1 gal | |
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CHIH 11 MEX 16 17 mi, 18 min
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| Páramo de Morelos | 24 mi | 26 min | 0.6 gal | |
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MEX 16 17 mi, 18 min
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| Cuauhtémoc | 42 mi | 45 min | 1.3 gal | |
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MEX 16 6 mi, 06 min
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| Guadalupe Victoria (Santa Lucía) | 47 mi | 52 min | 1.5 gal | |
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MEX 16 7 mi, 07 min
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| Cieneguilla | 54 mi | 1 h 00 min | 1.7 gal | |
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MEX 16 11 mi, 12 min
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| El Aguaje | 66 mi | 1 h 12 min | 2.2 gal | |
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MEX 16 6 mi, 07 min
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| Santa Isabel | 72 mi | 1 h 19 min | 2.3 gal | |
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MEX 16 12 mi, 12 min
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| Rancho de Peña | 84 mi | 1 h 32 min | 2.6 gal | |
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MEX 24 29 mi, 34 min
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| San Francisco Javier de Satevó | 114 mi | 2 h 06 min | 3.8 gal | |
Frequently Asked Questions
How many toll booths are there from Vicente Guerrero to San Francisco Javier de Satevó?
There are 1 tollbooth between Vicente Guerrero and San Francisco Javier de Satevó: Cuauhtémoc.
How much does the toll booths cost from Vicente Guerrero to San Francisco Javier de Satevó?
Toll roads cost: Cuauhtémoc (110 MXN) = 110 MXN
How much does it cost to drive from Vicente Guerrero to San Francisco Javier de Satevó?
Fuel cost: 15.2 USD
This fuel cost is calculated as: (Route length 113.7 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.93 USD / gal)
You can adjust fuel consumption and fuel price here.
Toll roads cost: 110 MXN
How long is a car ride from Vicente Guerrero to San Francisco Javier de Satevó?
Driving time: 2 h 6 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 42 mi with a maximum speed 56 mph = 44 min
- 34 mi with a maximum speed 56 mph = 35 min
- 39 mi with a maximum speed 50 mph = 46 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Vicente Guerrero to San Francisco Javier de Satevó by land?
The distance between Vicente Guerrero and San Francisco Javier de Satevó is 113.7 mi by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Vicente Guerrero and San Francisco Javier de Satevó respectively.
How far is Vicente Guerrero to San Francisco Javier de Satevó by plane?
The shortest distance (air line, as the crow flies) between Vicente Guerrero and San Francisco Javier de Satevó is 93.2 mi.
This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Vicente Guerrero and San Francisco Javier de Satevó respectively. Actual distance between airports may be different.
How many hours is Vicente Guerrero from San Francisco Javier de Satevó by plane?
Boeing 737 airliner needs 11 min to cover the distance of 93 mi at a cruising speed of 497 mph.
Small plane "Cessna 172" needs 40 min to flight this distance at average speed of 136 mph.
This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.
How long is a helicopter ride from Vicente Guerrero to San Francisco Javier de Satevó?
Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 37 min to cover the distance of 93 mi at a cruising speed of 149 mph.
Popular "Robinson R44" needs 42 min to flight this distance at average speed of 130 mph.
This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.
What city is halfway between Vicente Guerrero and San Francisco Javier de Satevó?
The halfway point between Vicente Guerrero and San Francisco Javier de Satevó is Cieneguilla. It is located about 2 mi from the exact midpoint by road.
The distance from Cieneguilla to Vicente Guerrero is 54 mi and driving will take about 1 h. The road between Cieneguilla and San Francisco Javier de Satevó has length 59 mi and will take approximately 1 h 6 min.
The other cities located close to halfway point:
Where is Vicente Guerrero in relation to San Francisco Javier de Satevó?
Vicente Guerrero is located 93 mi north-west of San Francisco Javier de Satevó.
Vicente Guerrero has geographic coordinates: latitude 28.54784, longitude -107.48338.
San Francisco Javier de Satevó has geographic coordinates: latitude 27.95573, longitude -106.10643.
Which highway goes from Vicente Guerrero to San Francisco Javier de Satevó?
The route from Vicente Guerrero to San Francisco Javier de Satevó follows MEX 16.
Other minor sections pass along the road:
- MEX 24: 31 mi
- CHIH 11: 12 mi