Distance between Waterford MN and Faribault MN
The distance from Waterford to Faribault is 16 miles by road. Road takes approximately 19 minutes and goes through Northfield and Dundas.
Shortest distance by air | 14 mi ✈️ |
Car route length | 15.5 mi 🚗 |
Driving time | 19 min |
Fuel amount | 0.5 gal |
Fuel cost | 2 USD |
Point | Distance | Time | Fuel | |
Waterford | 0 mi | 00 min | 0.0 gal | |
CR 47 2 mi, 03 min
|
||||
Northfield | 2 mi | 03 min | 0.0 gal | |
MN 3 2 mi, 03 min
|
||||
Dundas | 5 mi | 06 min | 0.2 gal | |
MN 3 11 mi, 12 min
|
||||
Faribault | 16 mi | 19 min | 0.5 gal |
Hotels of Faribault
Frequently Asked Questions
How much does it cost to drive from Waterford to Faribault?
Fuel cost: 2 USD
This fuel cost is calculated as: (Route length 15.5 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.82 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Waterford to Faribault?
Driving time: 19 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 10 mi with a maximum speed 56 mph = 10 min
- 1 mi with a maximum speed 55 mph = 1 min
- 2 mi with a maximum speed 50 mph = 1 min
- 1 mi with a maximum speed 31 mph = 2 min
- 1 mi with a maximum speed 30 mph = 1 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Waterford to Faribault by land?
The distance between Waterford and Faribault is 15.5 mi by road.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Waterford and Faribault respectively.
Where is Waterford in relation to Faribault?
Waterford is located 14 mi north-east of Faribault.
Waterford has geographic coordinates: latitude 44.48385, longitude -93.14299.
Faribault has geographic coordinates: latitude 44.29496, longitude -93.26883.
Which highway goes from Waterford to Faribault?
The route from Waterford to Faribault follows MN 3.