Distance between Waterloo IA and Osage IA
The distance from Waterloo to Osage is 70 miles by road including 29 miles on motorways. Road takes approximately 1 hour and 12 minutes and goes through Cedar Falls, Charles City, Janesville, Plainfield and Floyd.
| Shortest distance by air | 60 mi ✈️ |
| Car route length | 70.2 mi 🚗 |
| Driving time | 1 h 12 min |
| Fuel amount | 2.4 gal |
| Fuel cost | 9.3 USD |
| Point | Distance | Time | Fuel | |
| Waterloo | 0 mi | 00 min | 0.0 gal | |
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US 218 7 mi, 08 min
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| Cedar Falls | 7 mi | 08 min | 0.2 gal | |
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US 218 7 mi, 06 min
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| Janesville | 14 mi | 14 min | 0.5 gal | |
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US 218 17 mi, 16 min
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| Plainfield | 31 mi | 31 min | 1.0 gal | |
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US 218 16 mi, 16 min
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| Charles City | 47 mi | 47 min | 1.6 gal | |
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US 218 10 mi, 09 min
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| Floyd | 57 mi | 57 min | 1.8 gal | |
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US 18 CR T38 14 mi, 14 min
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| Osage | 70 mi | 1 h 12 min | 2.3 gal | |
Hotels of Osage
Frequently Asked Questions
How much does it cost to drive from Waterloo to Osage?
Fuel cost: 9.3 USD
This fuel cost is calculated as: (Route length 70.2 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.9 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Waterloo to Osage?
Driving time: 1 h 12 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 28 mi with a maximum speed 65 mph = 25 min
- 35 mi with a maximum speed 56 mph = 37 min
- 7 mi with a maximum speed 50 mph = 9 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Waterloo to Osage by land?
The distance between Waterloo and Osage is 70.2 mi by road including 29.2 mi on motorways.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Waterloo and Osage respectively.
How far is Waterloo to Osage by plane?
The shortest distance (air line, as the crow flies) between Waterloo and Osage is 59.7 mi.
This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Waterloo and Osage respectively. Actual distance between airports may be different.
How many hours is Waterloo from Osage by plane?
Boeing 737 airliner needs 7 min to cover the distance of 60 mi at a cruising speed of 497 mph.
Small plane "Cessna 172" needs 26 min to flight this distance at average speed of 136 mph.
This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.
How long is a helicopter ride from Waterloo to Osage?
Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 24 min to cover the distance of 60 mi at a cruising speed of 149 mph.
Popular "Robinson R44" needs 27 min to flight this distance at average speed of 130 mph.
This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.
What city is halfway between Waterloo and Osage?
The halfway point between Waterloo and Osage is Plainfield. It is located about 4 mi from the exact midpoint by road.
The distance from Plainfield to Waterloo is 31 mi and driving will take about 31 min. The road between Plainfield and Osage has length 39 mi and will take approximately 41 min.
The other cities located close to halfway point:
Where is Waterloo in relation to Osage?
Waterloo is located 60 mi south-east of Osage.
Waterloo has geographic coordinates: latitude 42.49829, longitude -92.33687.
Osage has geographic coordinates: latitude 43.28408, longitude -92.81116.
Which highway goes from Waterloo to Osage?
The route from Waterloo to Osage follows IA 27, US 218.
Other minor sections pass along the road:
- US 18: 12 mi
- CR T38: 6 mi