The distance from Jackson to Fountain Hills is 1,486 miles by road including 1,466 miles on motorways. Road takes approximately 23 hours and 31 minutes and goes through Longview, Mesquite, Dallas, Arlington, Abilene, Midland and Odessa.
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How long is a car ride from Jackson to Fountain Hills?
Driving time:
23 h 31 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
875 mi with a maximum speed 68 mph = 12 h 52 min
65 mi with a maximum speed 65 mph = 1 h
297 mi with a maximum speed 62 mph = 4 h 46 min
31 mi with a maximum speed 60 mph = 30 min
12 mi with a maximum speed 56 mph = 13 min
204 mi with a maximum speed 50 mph = 4 h 5 min
1 mi with a maximum speed 45 mph = 1 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Jackson to Fountain Hills by land?
The distance between Jackson and Fountain Hills is 1,485.7 mi by road including 1,466.4 mi on motorways.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Jackson and Fountain Hills respectively.
How far is Jackson to Fountain Hills by plane?
The shortest distance (air line, as the crow flies) between Jackson and Fountain Hills is 1,249.6 mi.
This distance is calculated using the Haversine formula as a great-circle distance between two points on the surface of a sphere. The start and finish points are the centers of Jackson and Fountain Hills respectively. Actual distance between airports may be different.
How many hours is Jackson from Fountain Hills by plane?
Boeing 737 airliner needs 2 h 30 min to cover the distance of 1,250 mi at a cruising speed of 497 mph.
Small plane "Cessna 172" needs 9 h 8 min to flight this distance at average speed of 136 mph.
This time is approximate and do not take into account takeoff and landing times, airport location and other real world factors.
How long is a helicopter ride from Jackson to Fountain Hills?
Fast helicopter "Eurocopter AS350" or "Hughes OH-6 Cayuse" need 8 h 22 min to cover the distance of 1,250 mi at a cruising speed of 149 mph.
Popular "Robinson R44" needs 9 h 34 min to flight this distance at average speed of 130 mph.
This time is approximate and do not take into account takeoff and landing times, aerodrome location and other real world factors.
What city is halfway between Jackson and Fountain Hills?
The halfway point between Jackson and Fountain Hills is Midland. It is located about 6 mi from the exact midpoint by road.
The distance from Midland to Jackson is 737 mi and driving will take about 11 h 50 min. The road between Midland and Fountain Hills has length 749 mi and will take approximately 11 h 41 min.
The other cities located close to halfway point:
Odessa is in 751 mi from Jackson and 735 mi from Fountain Hills
Penwell is in 772 mi from Jackson and 714 mi from Fountain Hills
Stanton is in 714 mi from Jackson and 772 mi from Fountain Hills
Where is Jackson in relation to Fountain Hills?
Jackson is located 1,250 mi east of Fountain Hills.
Jackson has geographic coordinates: latitude 32.29904, longitude -90.18477.
Fountain Hills has geographic coordinates: latitude 33.61171, longitude -111.71736.
Which highway goes from Jackson to Fountain Hills?
The route from Jackson to Fountain Hills follows I 20, I 10, US 70, US 180.