Distance between Faribault MN and Medford MN
The distance from Faribault to Medford is 11 miles by road including 8 miles on motorways. Road takes approximately 11 minutes and goes through Owatonna.
Shortest distance by air | 9 mi ✈️ |
Car route length | 11.2 mi 🚗 |
Driving time | 11 min |
Fuel amount | 0.4 gal |
Fuel cost | 1.5 USD |
Point | Distance | Time | Fuel | |
Faribault | 0 mi | 00 min | 0.0 gal | |
I 35 11 mi, 11 min
|
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Medford | 11 mi | 11 min | 0.3 gal |
Frequently Asked Questions
How much does it cost to drive from Faribault to Medford?
Fuel cost: 1.5 USD
This fuel cost is calculated as: (Route length 11.2 mi) / (Fuel consumption 29.4 mpg) * (Fuel price 3.93 USD / gal)
You can adjust fuel consumption and fuel price here.
How long is a car ride from Faribault to Medford?
Driving time: 11 min
This time is calculated for driving at the maximum permitted speed, taking into account traffic rules restrictions.
- 7 mi with a maximum speed 68 mph = 6 min
- 3 mi with a maximum speed 50 mph = 3 min
The calculated driving time does not take into account intermediate stops and traffic jams.
How far is Faribault to Medford by land?
The distance between Faribault and Medford is 11.2 mi by road including 8.1 mi on motorways.
Precise satellite coordinates of highways were used for this calculation. The start and finish points are the centers of Faribault and Medford respectively.
Where is Faribault in relation to Medford?
Faribault is located 9 mi north of Medford.
Faribault has geographic coordinates: latitude 44.29496, longitude -93.26883.
Medford has geographic coordinates: latitude 44.17413, longitude -93.24632.
Which highway goes from Faribault to Medford?
The route from Faribault to Medford follows I 35.
Other minor sections pass along the road:
- I 35 Business: 2 mi
- CR 12: 1 mi